Consider the following reaction: 3PbCl2 + 2(NH4)3PO4 Pb3(PO4)2 + 6NH4Cl If 72 mmol of PbCl2 is mixed with 50 mmol of (NH4)3PO4 , then amount of Pb3(PO4)2 formed | JEE Mains Chemistry Past Papers β€” Chem-Mantra | Chem-Mantra