Consider the following reaction: 3PbCl2 + 2(NH4)3PO4 Pb3(PO4)2 + 6NH4Cl If 72 mmol of PbCl2 is mixed with 50 mmol of (NH4)3PO4 , then amount of Pb3(PO4)2 formed is …… mmol. (nearest integer)

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Question

Prashant Kotian · Accepted Answer

Correct answer: .. Limiting Reagent is PbCl2 mmol of Pb3(PO4)2 formed = mmol of PbCl reacted = 24 mmol

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