See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

(P) (1, 5), (Q) (1), (R) (3), (S) (4) (1)   2 3 3 2 , Sn NO Sn NO    2 Sncan further oxidize into 4 Snand It is basic radical 3 NOcan’t further oxidize. (2) 3 2 , KNO K NO    K can’t be further oxidize but 2 NOcan be oxidize into 3 NO (3) 2 2 2 4 4 , FeC O Fe CO    Fecan be oxidize into 2 CO so both radical (4) 2 3 3 , NaCO Na CO    both ions can’t be oxidized further so no radical (5) 2 2 3 3 , BaSO Ba SO    2 Ba can’t be oxidized but 2 3 SO can be oxidized into 2 4 SO only acid radical. SECTION – D