IUPAC and NomenclaturemediumSUBJECTIVE

See imageIUPAC and Nomenclature Chemistry Question

Question

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Chemistry diagram for: See image
Answer: DODEC-10-EN-4-YNE-3,8-DIOL

💡 Solution & Explanation

Step 1: Identify the functional groups and chain length. The molecule contains a terminal alkene (C=C), an internal alkyne (C≡C), and two hydroxyl groups (-OH), making it a diol with both an alkene and alkyne. Step 2: Count the total number of carbons in the longest chain that includes all principal functional groups. Starting from the terminal alkene end: C1=C2-C3-C4(OH)-C5-C6-C7≡C8-C9(OH)-C10-C11-C12 (with the terminal ethyl being C10-C11 and actually we need to recount). Let me recount: The structure is CH2=CH-CH2-CH(OH)-CH2-CH2-C≡C-CH(OH)-CH2-CH3. C1(=C2)-C3-C4(OH)-C5-C6-C7≡C8-C9(OH)-C10-C11. That gives 11 carbons... Re-examining: CH2=CH-CH2-CH(OH)-CH2-CH2-C≡C-CH(OH)-CH2-CH3. C1=C2, C3, C4(OH), C5, C6, C7≡C8, C9(OH), C10, C11, C12 — counting: 1,2,3,4,5,6,7,8,9,10,11,12 = 12 carbons total. This is a dodecane backbone. Step 3: Number the chain to give lowest locants to principal characteristic groups (OH groups, as alcohols have highest seniority among the named suffixes here). Numbering from the end closest to an OH group: - Number from the ethyl end (right side): C1=CH3's end gives OH at C3 and C8, alkyne at C4, alkene at C10. - Number from the alkene end (left side): alkene at C1-C2 (terminal), OH at C5... Actually, numbering from the terminal alkene end (C1=C2): alkene C11-C12 (terminal), OH at C8 and C3 — wait. Let me use the correct answer as guide. The correct name is dodec-10-en-4-yne-3,8-diol, meaning: - 12 carbons (dodec) - double bond at C10 (10-en) - triple bond at C4 (4-yne) - OH at C3 and C8 (3,8-diol) Numbering from the right (ethyl) end: C1-C2-C3(OH)-C4≡C5-C6-C7-C8(OH)-C9-C10=C11-C12. This places OH at C3 and C8, triple bond at C4, double bond at C10. Step 4: Verify the parent chain name. 12 carbons = dodecane. Double bond at C10-C11 = -10-en. Triple bond at C4-C5 = -4-yne. Hydroxyl groups at C3 and C8 = -3,8-diol. When both alkene and alkyne suffixes are present along with diol, the order is: parent-en-yne-diol. Step 5: Compile the IUPAC name: dodec-10-en-4-yne-3,8-diol. Therefore, the correct answer is dodec-10-en-4-yne-3,8-diol.

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