During the qualitative analysis of SO32– using dilute H2SO4, SO2 gas is evolved which turns K2Cr2O7 — JEE Mains Chemistry Past Papers Chemistry Question
Question
During the qualitative analysis of SO32– using dilute H2SO4, SO2 gas is evolved which turns K2Cr2O7 solution (acidified with dilue H2SO4) : (A) red (B) blue (C) green (D) black
Answer: C
💡 Solution & Explanation
ution (acidified with dilue H2SO4) : (1) red (2) blue (3) green (4) black NTA. (3) RESO. (3) Sol. Cr2O7 –2 + 14H+ + 6e– 2Cr3+ + 7H2O (Orange Red) (Green) | JEE(Main) 2023 | DATE : 30-01-2023 (SHIFT-1) | PAPER-1 | OFFICIAL PAPER | CHEMISTRY PAGE # 2
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