See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Initially Pm = PºX.XX + PºY.XY 550 = PºX       3 1 1 + PºY       3 1 3 or P°X + 3P°Y = 2200 ...(i) When 1 mole of Y is further added to it Pm = PºX.XX + PºY.XY 560 = PºX       4 1 1 + PºY       4 1 4  P°X + 4P°Y = 2800 ...(ii) By eqs. (i) and (ii) PºX = 400 mm and P°Y = 600 mm. AITS-FT-I (Paper-1)-PCM(Sol.)-JEE(Advanced)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 8 Mathematics PART – III Section – A