If at initial temperature, T1, E1 is the internal energy and at higher temperature T2, E2 is the int — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

Since the process is adiabatic (q = 0) and the vessel is rigid (constant volume, so work w = 0), by the First Law of Thermodynamics: ΔE = q + w = 0. Thus, the internal energy of the system remains constant (E1 = E2).