The K for bismuth sulphide (Bi S ) is 1.08 × 10 . The solubility of Bi S in mol L at 298 K is sp 2 3 — Ionic Equilibrium Chemistry Question
Question
The K for bismuth sulphide (Bi S ) is 1.08 × 10 . The solubility of Bi S in mol L at 298 K is sp 2 3 –73 2 3 –1 –15 –12 –10 –8 sp 3+ 2 2– 3 2 3 5 sp –73 –15 (A) 1.0 × 10 (B) 2.7 × 10 (C) 3.2 × 10 (D) 4.2 × 10
Answer: A) 1.0 × 10
💡 Solution & Explanation
k = [Bi ] . [S ] = (2s) . (3s) = 108 s k = 1.08 × 10 s = 10 mol/L
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