A solution of Na2SO4 in water is electrolysed using inert electrodes. The products at cathode and an — Metallurgy and Isolation of Elements Chemistry Question

💡 Solution & Explanation

Step 1: In the electrolysis of an aqueous solution of sodium sulfate (Na2SO4) using inert electrodes, we analyze the competitive discharge of ions at the electrodes. Step 2: At the cathode, the reduction of water (H2O + e^- -> 1/2 H2 + OH^-) has a much more favorable reduction potential than the reduction of sodium ions (Na^+ + e^- -> Na). Thus, H2 gas is evolved at the cathode. Step 3: At the anode, the oxidation of water (H2O -> 1/2 O2 + 2H^+ + 2e^-) occurs preferentially over the oxidation of sulfate ions (SO4^2-). Thus, O2 gas is evolved at the anode. The products are H2 and O2 respectively, matching option (c).