See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

1 k A B P       1 k P A B  2 k P Q   2 Rate k P … (1) Applying steady state assumption on [P]     1 1 2 d P k A B k P K P 0 dt         1 1 2 k A B k P k P       1 1 2 k A B P k k    … (2) From (1) and (2) Rate  2 1 1 2 k k A B k k    2 1 overall 1 2 k k k k k    5 4 10