The translational kinetic energy of 10^20 molecules of nitrogen at a certain temperature is 0.63 J. — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

KE = 1.5 * N * k_B * T => 0.63 = 1.5 * 10^20 * 1.38*10^-23 * T => 0.63 = 2.07*10^-3 * T => T = 304.3 K . Celsius temperature = 304.3 - 273 = 31.3°C .