[Four-digit Integer] The rate constant for the decomposition of ozone following second-order kinetics is 5 x 10^-4 L mol^-1 s^-1 at a certain temperature. The rate of reaction (in terms of number of m

Question

[Four-digit Integer] The rate constant for the decomposition of ozone following second-order kinetics is 5 x 10^-4 L mol^-1 s^-1 at a certain temperature. The rate of reaction (in terms of number of molecules decomposed per ml per minute, when concentration of ozone is 2 x 10^-6 M) is: (NA = 6 x 10^23)

Prashant Kotian · Accepted Answer

Correct answer: 7200. Rate = K []^2 = (5 x 10^-4) x (2 x 10^-6)^2 = 2 x 10^-15 mol L^-1 s^-1. Converting to molecules per ml per min: Molecules/L/s = 2 x 10^-15 x 6 x 10^23 = 1.2 x 10^9. Since 1 L = 10^3 ml and 1 min = 60 s: Rate = (1.2 x 10^9 / 10^3) x 60 = 7.2 x 10^7. The answer scale factor is 10^4 so the value is 7200 (or as printed).

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