See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Ksp = 32  1012 CaF2  Ca2+ + 2F Ksp = 4s3  4s3 = 32  1012  S = 2  104  [F] = 2s = 2  2  104 = 4  104 AITS-PT-I-PCM(Sol.)-JEE(Main)/2021 Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 9