See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Triatomic linear gas molecule 1KT 5 2   5 KT 2  Triatomic angular gas molecule 1KT 6 2   = 3 KT Monoatomic gas molecule 1KT 3 2   3 KT 2  Ratio 5 / 2 KT 5 3 / 2 KT 3   Ratio 3KT 2 3 / 2 KT   Ans. 5 3 and 2