See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

25. D Sol. Drawing F.B.D. of rod PQ Fx = 0 Fy = 0  N = mg ….. (1)  about centre of mass = 0  N sin 2 N cos tan 2 2 2 l l              Hence   2 sec 4 /2   Thus, 2 2 4 / 2 4 1 2          l l  17