See image — IUPAC and Nomenclature Chemistry Question

💡 Solution & Explanation

Step 1 - Identify the parent structure: The molecule contains a benzene ring, making it an aromatic compound. Step 2 - Identify substituents: At one position (C1) of the benzene ring, there is a -COOH (carboxylic acid) group. At the para position (C4), there is a -COOC2H5 (ethyl ester) group. Step 3 - Determine the principal characteristic group for naming: In IUPAC nomenclature, when both a carboxylic acid and an ester are present, the carboxylic acid (-COOH) has higher seniority and is cited as the principal characteristic group, giving the suffix '-oic acid'. The base name is therefore 'benzoic acid'. Step 4 - Name the substituent: The ethyl ester group at C4 is named as a substituent prefix: -C(=O)OC2H5 is an 'ethoxycarbonyl' group. Step 5 - Assign locant: Since the -COOH defines C1, the ester at the opposite (para) position is C4, giving the prefix '4-(ethoxycarbonyl)'. Step 6 - Combine: The full IUPAC name is 4-(ethoxycarbonyl)benzoic acid. No other options are present to eliminate. Therefore, the correct answer is 4-(ethoxycarbonyl)benzoic acid.