At the sea level, the dry air mass percentage composition is given an nitrogen gas : 70.0, oxygen gas : 27.0 and argon gas : 3.0. If total pressure is 1.15 atm, then calculate the ratio of following r

Question

At the sea level, the dry air mass percentage composition is given an nitrogen gas : 70.0, oxygen gas : 27.0 and argon gas : 3.0. If total pressure is 1.15 atm, then calculate the ratio of following respectively : (i) partial pressure of nitrogen gas to partial pressure of oxygen gas (ii) partial pressure of oxygen gas to partial pressure of argon gas (Given : Molar mass of N, O and Ar are 14, 16 and 40g mol–1 respectively.)

(A) 4.26, 19.3
(B) 2.96, 11.2
(C) 2.59, 11.85
(D) 5.46, 17.8

Prashant Kotian · Accepted Answer

Correct answer: B. 2 O N P P = T O T N P . X P . X 2 = 2 O N n n {using Dalton's law of partial pressure} = / 28 / = 2.96 Ar O P P 2 = Ar O n n 2 = / 32 / = 11.25

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