When Cu2+ ion is treated with KI, a white precipitate, X appears in solution. The solution is titrated with sodium thiosuphate, the compound Y is formed. X and Y respectively are (A) X = Cul2 Y = Na2S

Question

When Cu2+ ion is treated with KI, a white precipitate, X appears in solution. The solution is titrated with sodium thiosuphate, the compound Y is formed. X and Y respectively are

(A) X = Cul2 Y = Na2S2O3
(B) X = Cul2 Y = Na2S4O6
(C) X = Cu2I2 Y = Na2S4O6
(D) X = Cu212 Y = Na2S4O5

Prashant Kotian · Accepted Answer

Correct answer: C. Cu2+ + 4I–  Cu2I2 + I2 White ‘X’ I2 + 2Na2S2O3  2Na2S4O6 + 2NaI ‘y’ x = Cu2I2 & y = Na2S4O6

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