See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let z1 = 1  |1 + z2| = |1 + cos  + i sin |2 = 2 + 2 cos   2 3   3 cos 2  or , 6 6         because z2  1 and 2k 42    k = 1, 2, 3  6 P 41 