GOC and Organic Chemistry BasicshardMATCH FOLLOWING

See imageGOC and Organic Chemistry Basics Chemistry Question

Question

See image

Chemistry diagram for: See image
Answer: {"A": "FORWARD", "B": "BACKWARD"}

💡 Solution & Explanation

Concept: These equilibria are governed by the relative stability of carbocations/carbanions and aromaticity/antiaromaticity. (a) Forward direction analysis: Reactant side: Cyclooctatetraene (COT) is a tub-shaped, non-planar, non-aromatic 8 pi-electron system. It acts as a hydride donor (losing H-) to Ph3C(+) (trityl cation, generated from Ph3CBr as an electrophilic hydride abstractor). Product side: The cyclooctatetraenyl cation (C8H8(+)) formed would be a 6 pi-electron system in a planar ring — this is aromatic (Huckel rule: 4n+2, n=1). Gaining aromatic stabilization of 6 pi electrons drives the reaction forward strongly. Ph3CH (triphenylmethane) is a stable neutral product. Therefore, the products are more stable than the reactants, and the equilibrium lies to the RIGHT (forward). (b) Backward direction analysis: Reactant side: The cyclopentadienyl anion (C5H5(-)) is a 6 pi-electron aromatic anion — extremely stable (pKa of cyclopentadiene ~16). CH4 is a very weak acid (pKa ~50). Product side: The cyclopentadiene (neutral, sp3 carbon with methyl) loses its aromaticity since the ring is now non-aromatic with the added methyl group disturbing the system. CH3(-) (methyl carbanion / KCH3) is an extremely strong base, far less stable than the aromatic cyclopentadienyl anion. The acidity comparison: cyclopentadiene (pKa ~16) vs methane (pKa ~50). The equilibrium always favors the weaker acid and weaker base on the product side. Here, reactants contain CH4 (weaker acid) and C5H5(-) K+ (weaker base relative to CH3(-)), so the equilibrium lies to the LEFT (backward) — the aromatic cyclopentadienyl anion is far more stable than CH3(-), so the reaction does not proceed forward. Why other directions fail: (a) Backward would require breaking aromaticity of the product cation — energetically unfavorable. (b) Forward would require the much stronger base CH3(-) to form at the expense of the aromatic stabilization of C5H5(-) — energetically unfavorable. Therefore, the correct answer is {"a": "forward", "b": "backward"}.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry