XCl2 (excess) + YCl2 XCl4 + Y ; YO 1/2 O2 + Y, Ore of Y would be : — Metallurgy and Isolation of Elements Chemistry Question
Question
XCl2 (excess) + YCl2 $\rightarrow$ XCl4 + Y $\downarrow$; YO $\xrightarrow{\Delta >400^\circ C}$ 1/2 O2 + Y, Ore of Y would be :
Answer: B
💡 Solution & Explanation
Step 1: Write down the net reaction for the reduction of ZnO by Carbon: ZnO(s) + C(s) -> Zn(s) + CO(g). Step 2: Calculate the standard Gibbs free energy change (ΔG°_reaction) for this net reaction: ΔG°_reaction = ΔG°_f(CO) - ΔG°_f(ZnO) = -460 kJ/mol - (-360 kJ/mol) = -100 kJ/mol. Step 3: Since the net Gibbs free energy change is negative (-100 kJ/mol), the reduction of ZnO by Carbon is thermodynamically spontaneous at 1000°C, meaning ZnO can be reduced to Zn by C (option b).
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes