What will be the decrease in level of mercury in the open arm at any time, t? — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

Since the area of the open arm (2A) is twice that of the closed arm (A), a rise of h in the closed arm corresponds to a fall of h/2 in the open arm. Thus, the decrease in the open arm is 76(1 - e^-kt) / 2 = 38(1 - e^-kt) cm.