See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let speed of the bullet = v Speed of the system after the collision = V By conservation of momentum V M m mv ) (    m M mv V   So the initial K.E. acquired by the system 2 ) ( 2 1 V m M   2 ) ( 2 1          m M mv M m = ) ( 2 1 2 2 M m v m  This kinetic energy goes against friction work done by friction = x g M m x R     ) (   By the law of conservation of energy ) ( 2 1 2 2 M m v m  x g M m    ) (   2 2 2         m M m gx v           m m M gx v  2 M m x v V For More Material Join: @JEEAdvanced_2024 AITS-CRT-II-PCM(Sol.)-JEE(Main)/2024 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 5