9.3 g of pure aniline upon diazotisation followed by coupling with phenol gives an orange dye. The m — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

NH2 NaNO2 + HCl N2 Cl + T < 5°C OH N = N HO Orange dye Reaction suggests that 1 mole of aniline give 1 mole of orange dye. so (mol)aniline = (mole)orange dye 1 9.3g mass of orange dye 93g mol 199g mol    mass of orange dye = 19.9 g 20 g