An ideal solution was obtained by mixing methanol and ethanol. If the partial vapour pressures of methanol and ethanol are 2.8 and 4.2 kPa respectively, the mole fraction of methanol in the vapour at

Question

An ideal solution was obtained by mixing methanol and ethanol. If the partial vapour pressures of methanol and ethanol are 2.8 and 4.2 kPa respectively, the mole fraction of methanol in the vapour at equilibrium is

Prashant Kotian · Accepted Answer

Correct answer: B. Total vapour pressure P_total = p_methanol + p_ethanol = 2.8 + 4.2 = 7.0 kPa. The mole fraction of methanol in the vapour phase (Y_methanol) is given by: Y_methanol = p_methanol / P_total = 2.8 / 7.0 = 0.4.

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