For a first-order reaction, t_0.75 = 1386 s. Its specific reaction rate is — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

For a first-order reaction, t_0.75 = 2 × t_1/2 => t_1/2 = 1386/2 = 693 s. The rate constant (specific reaction rate) is K = ln2/t_1/2 = 0.693/693 = 10^-3 s^-1.