See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

By Arrhenius equation, For I. 1 1 E /RT 1 1 k A e  For II. 2 2 E /RT 2 2 k A e    2 1 E E /RT 1 1 2 2 k A e k A    For More Material Join: @JEEAdvanced_2024 AITS-FT-X-PCM(Sol.)-JEE(Main)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 13   3 4 15 30 /8.314 10 600 1 4 2 A 150 10 e A