See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Given that C = CV + 4R .....(1) Compare with dQ = dU + PdV CdT = CVdT + PdV V dV C C P dT   .....(2) We get, PdV 4R dT  RT dv 4R V dT  dT dv 4 T v    4 nT nV    4 VT const  Hence, n = 4 AITS-FT-VII-(Paper-2)-PCM (Sol.)-JEE(Advanced)/18 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 9 Chemistry PART – II SECTION – A