A quantity of 70 calories of heat is required to raise the temperature of 2 mole of an ideal gas at — Thermodynamics and Thermochemistry Chemistry Question
Question
A quantity of 70 calories of heat is required to raise the temperature of 2 mole of an ideal gas at constant pressure from 40°C to 50°C. The amount of heat required to raise the temperature of the same gas through the same range at constant volume is
Answer: D
💡 Solution & Explanation
At constant pressure: q_p = n * $C_p$ * dT => 70 = 2 * $C_p$ * (50 - 40) => 70 = 20 * $C_p$ => $C_p$ = 3.5 cal/mol-K. Since $C_p$ - $C_v$ = R, and R approx 2.0 cal/mol-K: $C_v$ = $C_p$ - R = 3.5 - 2.0 = 1.5 cal/mol-K. At constant volume: q_v = n * $C_v$ * dT = 2 * 1.5 * 10 = 30 calories.
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