The solubility of (s) in water at 298 K is about 6 moles per litre. Suppose you add 1 mole of (s) to β Thermodynamics and Thermochemistry Chemistry Question
Question
The solubility of $NaCl$(s) in water at 298 K is about 6 moles per litre. Suppose you add 1 mole of $NaCl$(s) to a litre of water. For the reaction: $NaCl$(s) + $H_2O$ -> $NaCl$(aq)
Answer: B
π‘ Solution & Explanation
Since 1 mole is less than solubility limit (6 moles/L), dissolution is spontaneous, so Ξ G < 0. Dissolution of salt increases disorder, so Ξ S > 0.
π¬Ask on WhatsApp β
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp β gets answered in minutes