See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let the relation between T and V 1 be n V K T        1  n V K T        0 0 4 2 and n V K T        0 0 1  n 4 2   2 1  n Therefore 2 1 1        V K T or  2 / 1 TV constant But for adiabatic process, TV-1 = constant   –1 = 2 1 or  = 2 3 2 2 / 3 3 3     sound rms V V AITS-CRT-IV-PCM(Sol.)-JEE(Main)/22 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 7