Consider the following data: Na(s) + ½ Cl2(g) → NaCl(s) ΔH° = - 411 kJ/mole-1 Na(s) → Na(g) — AITS & Test Series Chemistry Question
Question
Consider the following data: Na(s) + ½ Cl2(g) → NaCl(s) ΔH° = - 411 kJ/mole-1 Na(s) → Na(g) ΔH° = 107 kJ/mole Cl2(g) → 2Cl(g) ΔH° = - 242 kJ/mol For More Join: @IITJEE_Advanced Rankers Academy JEE Cl(g) + e- → Cl-(g) ΔH° = - 355 kJ/mole Na(g) → Na+(g) + e- ΔH° = 502 kJ/mole-1 Find out lattice energy of NaCl(s) A) -786 kJ mole-1 B) -628 kJ mol-1 C) -428 kJ mole-1 D) -393 kJ mole-1
Answer: A
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes