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Consider the following data: Na(s) + ½ Cl2(g) → NaCl(s)​ ​ ΔH° = - 411 kJ/mole-1 Na(s) → Na(g)​ ​ ​ AITS & Test Series Chemistry Question

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Consider the following data: Na(s) + ½ Cl2(g) → NaCl(s)​ ​ ΔH° = - 411 kJ/mole-1 Na(s) → Na(g)​ ​ ​ ΔH° = 107 kJ/mole Cl2(g) → 2Cl(g)​ ​ ​ ΔH° = - 242 kJ/mol For More Join: @IITJEE_Advanced Rankers Academy JEE ​ ​ Cl(g) + e- → Cl-(g)​ ​ ​ ΔH° = - 355 kJ/mole Na(g) → Na+(g) + e-​ ​ ​ ΔH° = 502 kJ/mole-1 Find out lattice energy of NaCl(s) A) -786 kJ mole-1 B) -628 kJ mol-1 C) -428 kJ mole-1 D) -393 kJ mole-1

Answer: A
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