See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Number of X atom left in unit cell 1 1 4 5 1 8 2      AITS-FT-II-PCM(Sol.)-JEE(Main)/20 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 8 32 5 4 23 8 8     Number of Y atom left in unit cell 1 4 4 1 2 4     Number of Z atom left in unit cell 8 2 6    Formula = 23 2 6 8 X Y Z = X23Y16Z48