See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

X(g) + nY(g)  XYn(g)     0 0 0 0 f f n f f H H XY (g) [ H X (g) n H Y (g)]     = –1100 – [275 + 80n] = –1375 – 80 n  average X – Y bond enthalpy = 309.2 kJ/mol  XYn = – (309.2) n (-309.2)n = –1375 – 80n n = 6  XYn  XY6