See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

  2 2 x x 2 2 n 1 n e P x P x e              2 2 x x n 2 2 n 0 n d P x e P x e dx           Pn(0) = constant term in   2 n/2 x n 2 n d n! e n 2 dx ! 2                (where n is even).