See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

(A) Adsorption (Physical or chemisorption) is an exothermic process. High energy of activation in chemisorption requires higher temperature (contrary of Le-Chatelier’s principle) (B) Adsorption is a spontaneous process so G < 0 at all temperature. (C) 1 2 1 k k p x m 1 k p   at low P, k1p < < 1 AITS-FT-X (Paper-1)-PCM(Sol.)-JEE(Advanced)/2021 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 11  1 2 x k k p m  or x p m        At high value of p, 1 < < k1p Then 1 2 1 k k p x constant m k p   (D) As S is always negative in adsorption, so the factor (–TS) has a positive value rendering G to be less negative.