See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

We have, F = (12 – 2t) or, ) 2 12 ( t dt dv m   , where m is the mass of the body or,         m t dt dv 2 12     v t dt t m dv 0 0 ) 2 12 ( 1 or, v = m t t 2 12  or, m t t dt dx ) 12 ( 2       0 0 0 2 1 , ) 12 ( 1 t dt t t m dx where t1 is required time. or, 0 = ] 3 6 [ 1 3 1 2 1 t t m  P  R2 R1 +  d P R1 R2 x  10x x 1 P 2 P   T 400 C Ice at  0 C Water at  100 C For More Material Join: @JEEAdvanced_2024 Rankers Academy JEE AITS-FT-I-PCM(Sol.)-JEE(Main)/2024 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 7 or, t1 – 18 = 0 t1 = 18s