See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

As the metal gives white precipitates with NaCl and 2 2 3 Na S O both and white precipitate (Q) turns to black compound ‘R’ on standing hence the metal ‘M’ is ‘Ag’.      3 3 2 3Ag 4HNO dil. 3AgNO NO 2H O M N O       3 AgNO NaCl AgCl; P White     3 2 2 3 2 2 3 3 2AgNO Na S O Ag S O 2NaNO Q White    For More Material Join: @JEEAdvanced_2024 Rankers Academy JEE AITS-PT-III (Paper-2)-PCM(Sol.)-JEE(Advanced)/2024 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 10   2 2 3 2 3 2Ag S O Ag S SO Black    Amount of 3 AgNO formed 1 2  mole. Number of moles of 2 2 3 Ag S O formed 1 4  mole Weight of   2 2 3 1 Ag S O 108 2 2 32 3 16 4       = 82