See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

7A B t 0 a 0 b t 15hr a b 7     for point P  a – b = b 7 8b a 7   7a b 8  then a – b 7a a a 8 8    1/2 1/2 1/2 t 2t 3t a a a a 2 4 8    3 half lives will be 900 hrs AITS-FT-X (Paper-1)-PCM(Sol.)-JEE(Advanced)/20 Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 11  1/ 2 900 3t days 24 t1/2 = 12.5 days