Consider the dissociation of the weak acid HX as given below HX(aq) H+(aq) + X– (aq), Ka = 1.2 × 10– — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

HX  H+ + X– Ka = 1.2 × 10–5 0.03M 0.03 – x x x Ka = 1.2 × 10–5 = x 0.03 x  0.03 – x  0.03 (Ka is very small) x 0.03 = 1.2 × 10–5 x = 6 × 10–4 Final solution : 0.03 – x + x + x = 0.03 + x = 0.03 + 6 × 10–4  = (0.03 + (6 × 10–4)) × 0.083 × 300 = 76.19 × 10–2  76 × 10–2