Niobium (Nb) and ruthenium (Ru) have "x" and "y" number of electrons in their respective 4d orbitals — JEE Mains Chemistry Past Papers Chemistry Question
Question
Niobium (Nb) and ruthenium (Ru) have "x" and "y" number of electrons in their respective 4d orbitals. The value of x + y is ________.
Answer: .
💡 Solution & Explanation
41Nb[Kr]4d4, 5s1 44Ru[Kr]4d7, 5s1 Number of electrons in 4d = 4 + 7 = 11
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