The ratio between lowering of vapour pressure of solution and mole fraction of solute is equal to — Solutions and Colligative Properties Chemistry Question

💡 Solution & Explanation

According to Raoult's law: (P^o - P) / P^o = X_solute, where P^o is the vapour pressure of the pure solvent, P is the vapour pressure of the solution, and X_solute is the mole fraction of the solute. Rearranging this gives: (P^o - P) / X_solute = P^o. This means the ratio is equal to the vapour pressure of the pure solvent.