For two gases, A and B with molecular weights MA and MB, it is observed that at a certain temperature, T, the mean velocity of A is equal to the root mean square velocity of B. Thus the mean velocity

Question

For two gases, A and B with molecular weights MA and MB, it is observed that at a certain temperature, T, the mean velocity of A is equal to the root mean square velocity of B. Thus the mean velocity of A can be made equal to the mean velocity of B, if

Prashant Kotian · Accepted Answer

Correct answer: B. at temperature t: mean velocity of a is c_a = √(8rt / πm_a), and rms velocity of b is u_b = √(3rt / m_b). given c_a = u_b at temperature t: 8rt/πm_a = 3rt/m_b → m_b/m_a = 3π/8 ≈ 1.18. to make the mean velocities of a and b equal: c_a' = c_b' → t_a' / m_a = t_b' / m_b → t_a' / t_b' = m_a / m_b = 8 / (3π) < 1. if b is kept at t, then a must be at a lower temperature t' < t.

💡 Solution & Explanation

Practice 22,000+ questions like this