A metal M forms hexagonal close-packed structure. The total number of voids in 0.02 mol of it is ___ — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

Given mole of compound = 0.02 mol Number of atoms in 0.02 mol = 0.02 × 6 × 1023 = 12 × 1021 Number of octahedral voids = No. of atoms = 12 × 1021 Number of tetrahedral voids = 2 × No. of atoms = 2 × 12 × 1021 = 24 × 1021 Total number of voids = no. of octahedral voids + no. of tetrahedral voids Total no. voids in 0.02 mole compound = 12 × 1021 + 24 × 1021 = 36 × 1021