P(kPa) 20 D A V(dm3) B C Case - O P(kPa) 20 D 10 A V(dm3) B C Case - P(kPa) 20 D A V(dm3) B C Case - — JEE Mains Chemistry Past Papers Chemistry Question
Question
P(kPa) 20 D A V(dm3) B C Case - O P(kPa) 20 D 10 A V(dm3) B C Case - P(kPa) 20 D A V(dm3) B C Case - 25 An ideal gas undergoes a cyclic transformation starting from the point A and coming back to the same point by tracing the path A→B→C→D→A as shown in the three cases above. Choose the correct option regarding U: (A) U(Case-I) > U(Case-II) > U(Case-III) (B) U(Case-III) > U(Case-II) > U(Case-I) (C) U(Case-I) > U(Case-III) > U(Case-II) (D) U(Case-I) = U(Case-II) = U(Case-III)
Answer: D
💡 Solution & Explanation
In cyclic path change in state parameter is zero as internal energy is state parameter so U(Case-I) = U(Case-II) = U(Case-III) = 0 | JEE(Main) 2025 | DATE : 28-01-2025 (SHIFT-2) | PAPER-1 | CHEMISTRY PAGE # 2
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