In the sulphur estimation, 0.20 g of a pure organic compound gave 0.40 g of barium sulphate. The percentage of sulphur in the compound is __________ × 10–1%. (Molar mass : O = 16, S = 32, Ba = 137 in

Question

In the sulphur estimation, 0.20 g of a pure organic compound gave 0.40 g of barium sulphate. The percentage of sulphur in the compound is __________ × 10–1%. (Molar mass : O = 16, S = 32, Ba = 137 in g mol–1)

Prashant Kotian · Accepted Answer

Correct answer: .. Pure Organic compound  BaSO4 0.2 g 0.4 g Weight of sulphur in BaSO4 = Weight of sulphure in pure organic compound  % of sulphur in pure organic compound = 233 . × . 32 × 100 = 2 . 05493 .  = 27.46 % = 274.6 × 10–1 % = 275 × 10–1 % or BaSO n = 233 . ns = 233 . Ws = 233 . × 32 = 0.05493 %s = . 05493 . ×100 = 275 × 10–1 % Ans. 275

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