vap H for water is +40.49 kJ mol–1 at 1 bar and 100°C. Change in internal energy for this vapourisation under same condition is ______ kJ mol–1. (Integer answer) (Given R = 8.3 JK–1 mol–1)

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Prashant Kotian · Accepted Answer

Correct answer: .. 2 H O( ) H O(g) vap H 40.79kJ / mole   0 vap vap g H U n RT    vap 8.3 373.15 40.79 U     vap U 40.79 3.0971    37.6929  vap U 

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