The pH of 4.0 * 10^-4 M - solution is (log 2 = 0.3) — Ionic Equilibrium Chemistry Question
Question
The pH of 4.0 * 10^-4 M - $HNO_3$ solution is (log 2 = 0.3)
Answer: B
💡 Solution & Explanation
$HNO_3$ is a strong acid and dissociates completely. [H+] = 4.0 * 10^-4 M. pH = -log(4.0 * 10^-4) = 4 - log 4 = 4 - 2 log 2 = 4 - 0.6 = 3.4.
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