See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

(i)  V = 0  w = 0, q = U, H = Cp (T2 – T1), U = CV (T2 – T1) (ii) w = 0 , U = 0, H = 0, q = 0 For More Material Join: @JEEAdvanced_2024 AITS-CRT-IV (Paper-2)-PCM(Sol.)-JEE(Advanced)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 10 (iii) – w = P  V = P (V2 – V1) = R (T2 – T1) = -831.4  w = 831.4 Jmol-1 U = CV T H = CPT q = CVT - PV Total U = 0 Total H = 0 w = + 831.4 joule mol-1 q = - 831.4 joule mol-1