See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

By intermediate value property    f 0 f 2 f c , 0 c 2 2     By mean value theorem     1 1 f 1 f 0 f ' c , 0 c 1         2 2 f 2 f 1 f ' c , 1 c 2     By subtraction        2 1 f 0 f 2 2f 1 f ' c f ' c           2 1 1 2 c c f " c , c c c f 0 f 2 2f 1 0            f 0 f 2 2f 1   