, a toxic gas with rotten egg like smell, is used for the quantitative analysis. If the solubility of in water at STP is 0.192 m (approximated as 0.2 m in image), Henry's law constant for in water at

Question

$H_2S$, a toxic gas with rotten egg like smell, is used for the quantitative analysis. If the solubility of $H_2S$ in water at STP is 0.192 m (approximated as 0.2 m in image), Henry's law constant for $H_2S$ in water at 273 K is

Prashant Kotian · Accepted Answer

Correct answer: D. 0.2 mol in 1000 g water. Moles water = 55.56. x_H2S = 0.2/(0.2+55.56) = 3.587*10^-3. p = 10^5 Pa (STP). KH = p/x = 10^5/3.587*10^-3 = 2.78*10^7 Pa.

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